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Math Help - need help

  1. #1
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    need help

    Table 1.9 shows some values of a linear function f and an exponential function g. Find exact values (not decimal approximations) for each of the missing entries of f, and round your answers for g to 3 decimals.


    Table1.9 x 0 1 2 3 4

    f(x) 15 30
    g(x) 15 30


    i just really do not know how to do this one...please help

    mathlete
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by mathlete View Post
    Table 1.9 shows some values of a linear function f and an exponential function g. Find exact values (not decimal approximations) for each of the missing entries of f, and round your answers for g to 3 decimals.

    Code:
    Table1.9 x 0  1  2   3   4 
    
    f(x)         15     30   
    g(x)         15     30
    i just really do not know how to do this one...please help

    mathlete

    f(x)=mx+c

    determine m and c from the given data, and then fill in the missing values.

    g(x)=A e^{kx}

    determine A and k from the given data, and then fill in the missing values. This may be simplified by taking logs when you have:

    \ln(g(x))=k \ln(x) + \ln(A)

    RonL
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  3. #3
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    That's funny, I answered this in another thread.

    As I said there, you don't need to find the equations.

    f(2)-f(1)=f(1)-f(0)

    g(2)/g(1)=g(1)/g(0)
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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by a tutor View Post
    That's funny, I answered this in another thread.

    As I said there, you don't need to find the equations.

    f(2)-f(1)=f(1)-f(0)

    g(2)/g(1)=g(1)/g(0)

    Indeed you don't, but this won't work as it is either since the functional values at 1 and 3 are given not 0 and 2;
    or are they - difficult to tell from the original question

    RonL
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  5. #5
    Bar0n janvdl's Avatar
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    Quote Originally Posted by CaptainBlack View Post
    Indeed you don't, but this won't work as it is either since the functional values at 1 and 3 are given not 0 and 2;
    or are they - difficult to tell from the original question

    RonL
    On quoting it seems they are at 0 and 2, Captain.
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  6. #6
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    Quote Originally Posted by CaptainBlack View Post
    the functional values at 1 and 3 are given not 0 and 2;
    or are they - difficult to tell from the original question
    It is hard to tell. I took them to be values for x=0 and x=1.

    In any case you can just use \sqrt{\frac{g(3)}{g(1)}} if the values were x=1 and x=3.
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