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Thread: Difference quotient

  1. January 21st 2008, 10:24 AM #1
    Amy
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    Difference quotient

    Find the difference quotient and simplify your answer.

    f\left(x \right)={x}^{3}+x,\frac{f\left(x+h \right)-f\left(x \right)}{h},h\neq0

    Thanks
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  2. January 21st 2008, 10:30 AM #2
    Krizalid
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    Quote Originally Posted by Amy View Post
    f\left(x \right)={x}^{3}+x
    Then f(x + h) = (x + h)^3 + (x + h).

    Now substitute and work with it, what do you get?
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  3. January 21st 2008, 10:31 AM #3
    colby2152
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    Quote Originally Posted by Amy View Post
    Find the difference quotient and simplify your answer.

    f\left(x \right)={x}^{3}+x,\frac{f\left(x+h \right)-f\left(x \right)}{h},h\neq0

    Thanks
    Plug and chug Amy!

    \frac{(x+h)^3+x+h-x^3-x}{h}=???
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  4. January 21st 2008, 08:50 PM #4
    Amy
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    O.K, O.K . I got Colby
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