Write an equation of a quadratic functon that satisfies each set of condtions.
a) the function has a minimum value of 6 at x=4.
b) The parabola is congruent to y = 3x^2 and has a minimum value of 7.
the answer for part a) y = 3(x-4)^2 + 6
b) y = 3x^2+ 7
these answers are from the back of my book.. it also says that "Answers may vary"... plz help me.. .thnx
So any answer of the form satisfies the given property. The book chose a = 3. Other concrete answers can be got by choosing a = 1, 2, 4, 1/2, ......
b) The turning point has y-coordinate y = 7. So k = 7 in the turning point form. In the turning point form, a 'controls the shape', so a = 3.
So any answer of the form satisfies the given properties. The book chose h = 0, probably the simplest answer. Other concrete answers can be got by choosing h = 1, 2, 3, -1, -2 -3, 1/2, -1/2, ......