Write an equation of a quadratic functon that satisfies each set of condtions.
a) the function has a minimum value of 6 at x=4.
b) The parabola is congruent to y = 3x^2 and has a minimum value of 7.
the answer for part a) y = 3(x-4)^2 + 6
b) y = 3x^2+ 7
these answers are from the back of my book.. it also says that "Answers may vary"... plz help me.. .thnx