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Write an equation of a quadratic functon that satisfies each set of condtions.
a) the function has a minimum value of 6 at x=4.
b) The parabola is congruent to y = 3x^2 and has a minimum value of 7.
the answer for part a) y = 3(x-4)^2 + 6
b) y = 3x^2+ 7
these answers are from the back of my book.. it also says that "Answers may vary"... plz help me.. .thnx(Doh)(Doh):(:(:confused:
your answers seem fine to meQuote:
Originally Posted by ruscutie100
a) The (minimum) turning point is at (4, 6). You're familiar with the turning point form of a parabola -Quote:
Originally Posted by ruscutie100
where the turning point is at (h, k) - right?
So any answer of the formsatisfies the given property. The book chose a = 3. Other concrete answers can be got by choosing a = 1, 2, 4, 1/2, ......
b) The turning point has y-coordinate y = 7. So k = 7 in the turning point form. In the turning point form, a 'controls the shape', so a = 3.
So any answer of the formsatisfies the given properties. The book chose h = 0, probably the simplest answer. Other concrete answers can be got by choosing h = 1, 2, 3, -1, -2 -3, 1/2, -1/2, ......
(Rofl) That's because the answers are taken from the back of the book! (Doh)Quote:
Originally Posted by Jhevon
ah, yes, i see :DQuote:
Originally Posted by mr fantastic
that's my line!Quote:
(Doh)
Ah yes. But I learnt it from you :DQuote:
Originally Posted by Jhevon
so i can pretty much put any value for a... thnxQuote:
Originally Posted by mr fantastica) The (minimum) turning point is at (4, 6). You're familiar with the turning point form of a parabola -
So any answer of the form
b) The turning point has y-coordinate y = 7. So k = 7 in the turning point form. In the turning point form, a 'controls the shape', so a = 3.
So any answer of the form
Yes, as long as it's positive.Quote:
Originally Posted by ruscutie100