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    Lightbulb decay

    17. The population of Springield was 3500 in 1940. Assuming the population is increasing at a rate of 3.2%, what will the population be in 2005?
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    Quote Originally Posted by rlarach View Post
    17. The population of Springield was 3500 in 1940. Assuming the population is increasing at a rate of 3.2%, what will the population be in 2005?
    Standard formula: P = P_0 e^kt

    where k is the % population growth rate divided by 100 and P_0 is the initial population.

    For your question, P_0 = 3500 (taking 1940 to be t = 0) and k = 3.2/100 = 0.032. Therefore P = .......

    Now sub t = 65 and solve for P.
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