for (ii) we want all the x's in the domain of p(x) AND q(x) (at the same time) for which
for (iii) we want all the x's in the range of q(x) that are in the domain of r(x)
for (iv) we want all the x's in the range of p(x) that are in the domain of s(x) and of course, we cannot have s(p(x)) = 0
sorry i didnt understand a single thing you just said, would you mind explaining or elaborating a bit more please?? except for the part that the denominator cant be zero..i understand that as the function will be undefined.
thanks, and also for the question i posted earlier about continuity..i got k=29...so thats the value where it would be continuous..am i correct? please check
for (iii). the range is the output values we can have. so for, say, q(x) the domain is the x's we can plug into q, while the output values q(x) are the range. for example. for the function y = x^2, the domain is all real x, because we can plug in anything we choose for x. however, the output values are "limited", no matter what we plug in, we will always get an output value greater than or equal to zero, so the range of y = x^2 is all y's such that or in other words, . a similar thing holds here.
when we say r(q(x)), it means we are taking the outputs from the function q and plugging them into the function r. so first, we need to know what are the possible output values for q, and then we need to know, which of these values are in the domain of r. those are the values that are in the domain of r(q(x))
a similar thing holds true for (iv)
please make this comment in the thread that you are refering to, so other users can followthanks, and also for the question i posted earlier about continuity..i got k=29...so thats the value where it would be continuous..am i correct? please check
incorrect. both p(x) and q(x) are polynomials, all x's work in them. thus our only concern here is that q(x) is not zero. what x's make that happen?(ii) (-infinity, 2/3) U (2, infinity)
correct(iii) (-infinity, -2) U (2, infinity)
here we have to choose those x's that makes (why is that?)(iv)..no idea
so what's the answer?