Thread: Calculating intercept and gradient

Hey, I am going through an exam paper and can't work out how to do this question, can someone show me how to work it out please

Given that y= 4x^3
a)What is the value of the intercept on the Y axis obtained by plotting log (y) against log (x)
b) What is the gradient obtained by plottin log(y) against log(x)

Thankyou ^^

y = 4x^3

log(y) = log(4) + 3*log(x)

You should recognize this as the Slope-Intercept form of a line.

y = m*x + b

m = Slope = Gradient = 3

b = Intercept = log(4)

Thats quite easy, thankyou