y = 4x^3
log(y) = log(4) + 3*log(x)
You should recognize this as the Slope-Intercept form of a line.
y = m*x + b
m = Slope = Gradient = 3
b = Intercept = log(4)
Hey, I am going through an exam paper and can't work out how to do this question, can someone show me how to work it out please
Given that y= 4x^3
a)What is the value of the intercept on the Y axis obtained by plotting log (y) against log (x)
b) What is the gradient obtained by plottin log(y) against log(x)
Thankyou ^^