Find the inverses of the following functions.

i) $\displaystyle y = \frac {4x - 1}{3x + 2}$

$\displaystyle x = \frac {4 - 1}{3y + 2}$

$\displaystyle x(3y + 2) = 4y - 1$

$\displaystyle x(3y + 2) + 1 = 4y$

$\displaystyle 3xy + 2x + 1 = 4y$

$\displaystyle \frac {3xy + 2x + 1}{4} = y$

$\displaystyle 2x + 1 = y - \frac {3xy}{4}$

This is how far I got. . .and I don't know what to do now. . .