Thread: Finding the Domain and Range for. . .

$\displaystyle g(x) = \sqrt{1 - x^2}$

I know you set it into a rational equality

so. . .

$\displaystyle 1 - x^2 > 0$

And now what?

Originally Posted by Macleef

$\displaystyle 1 - x^2 > 0$
And now what?

$\displaystyle 1 > x^2 $?

Following Plato's Hint we have $\displaystyle |x|\le1\implies -1\le x\le1.$ (It's actually greater or equal than zero, the condition of course.)