Results 1 to 3 of 3

Thread: Finding the Domain and Range for. . .

  1. Jan 9th 2008, 04:37 PM #1
    Macleef
    Macleef is offline
    Member
    Joined
    Nov 2007
    Posts
    232

    Finding the Domain and Range for. . .

    g(x) = \sqrt{1 - x^2}

    I know you set it into a rational equality

    so. . .

    1 - x^2 > 0

    And now what?
    Follow Math Help Forum on Facebook and Google+
  2. Jan 9th 2008, 04:45 PM #2
    Plato
    Plato is online now
    MHF Contributor
    Joined
    Aug 2006
    Posts
    20,281
    Thanks
    2217
    Awards
    1
    MHF Donor
    Quote Originally Posted by Macleef View Post
    1 - x^2 > 0
    And now what?
    1 > x^2 ?
    Follow Math Help Forum on Facebook and Google+
  3. Jan 9th 2008, 05:22 PM #3
    Krizalid
    Krizalid is offline
    Math Engineering Student
    Krizalid's Avatar
    Joined
    Mar 2007
    From
    Santiago, Chile
    Posts
    3,656
    Thanks
    15
    Following Plato's Hint we have |x|\le1\implies -1\le x\le1. (It's actually greater or equal than zero, the condition of course.)
    Follow Math Help Forum on Facebook and Google+
« Inverse Function!! | solving system by substitution Help »

Similar Math Help Forum Discussions

  1. Finding Domain and Range
    Posted in the Calculus Forum
    Replies: 2
    Last Post: Dec 2nd 2010, 08:06 PM
  2. finding domain and range
    Posted in the Algebra Forum
    Replies: 2
    Last Post: Aug 8th 2008, 06:56 PM
  3. finding the domain and range
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: Nov 25th 2007, 05:35 PM
  4. Finding Domain and Range
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: Aug 29th 2007, 10:31 PM
  5. Finding the Domain and Range...
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: Jan 29th 2007, 03:59 PM

Search Tags


/mathhelpforum @mathhelpforum