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Thread: Finding the Domain and Range for. . .

  1. Jan 9th 2008, 05:37 PM #1
    Macleef
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    Finding the Domain and Range for. . .

    g(x) = \sqrt{1 - x^2}

    I know you set it into a rational equality

    so. . .

    1 - x^2 > 0

    And now what?
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  2. Jan 9th 2008, 05:45 PM #2
    Plato
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    Quote Originally Posted by Macleef View Post
    1 - x^2 > 0
    And now what?
    1 > x^2 ?
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  3. Jan 9th 2008, 06:22 PM #3
    Krizalid
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    Following Plato's Hint we have |x|\le1\implies -1\le x\le1. (It's actually greater or equal than zero, the condition of course.)
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