$\displaystyle g(x) = \sqrt{1 - x^2}$

I know you set it into a rational equality

so. . .

$\displaystyle 1 - x^2 > 0$

And now what?

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- Jan 9th 2008, 04:37 PMMacleefFinding the Domain and Range for. . .
$\displaystyle g(x) = \sqrt{1 - x^2}$

I know you set it into a rational equality

so. . .

$\displaystyle 1 - x^2 > 0$

And now what? - Jan 9th 2008, 04:45 PMPlato
- Jan 9th 2008, 05:22 PMKrizalid
Following Plato's Hint we have $\displaystyle |x|\le1\implies -1\le x\le1.$ (It's actually greater or equal than zero, the condition of course.)