# Finding the Domain and Range for. . .

• Jan 9th 2008, 04:37 PM
Macleef
Finding the Domain and Range for. . .
$g(x) = \sqrt{1 - x^2}$

I know you set it into a rational equality

so. . .

$1 - x^2 > 0$

And now what?
• Jan 9th 2008, 04:45 PM
Plato
Quote:

Originally Posted by Macleef
$1 - x^2 > 0$
And now what?

$1 > x^2$?
• Jan 9th 2008, 05:22 PM
Krizalid
Following Plato's Hint we have $|x|\le1\implies -1\le x\le1.$ (It's actually greater or equal than zero, the condition of course.)