# Thread: Factoring questions!, any help would be appreciated.

1. ## Factoring questions!, any help would be appreciated.

Hi all, i have two assigned questions i have completed one so i think and i was wondering if someone here wouldn't mind looking over it to see if i made any mistakes?

And the second one i'm completely stuck at this last stage,

I would appreciate any insight into these problems, Thanks!

2. ## Re: Factoring questions!, any help would be appreciated.

I agree, $a = \dfrac{k-3}{k+1}$

for the factoring problem, start by factoring out $(x+1)$ from each of the three terms, then go from there

3. ## Re: Factoring questions!, any help would be appreciated.

OH I DIDN'T EVEN SEE THAT!, Thanks Skeeter!

4. ## Re: Factoring questions!, any help would be appreciated.

-2(x^3 - 3x - 2)

S'that what you ended up with?

On your 1st one, you'd save time by dividing by 4 right after your 3rd step.....

5. ## Re: Factoring questions!, any help would be appreciated.

So Skeeter my final answer for that last question was -2(x-2)(x+1), Does that sound about right?

6. ## Re: Factoring questions!, any help would be appreciated.

$(x+1)\bigg[(4x-3)-(x^2-4)-(x^2+2x-3)\bigg]$

$(x+1)\bigg[-2x^2+2x+4\bigg]$

$-2(x+1)(x^2-x-2)$

$-2(x+1)(x-2)(x+1)$

$-2(x+1)^2(x-2)$

7. ## Re: Factoring questions!, any help would be appreciated.

Thanks Dennis and Skeeter.