The intercept will remain the same as the x value of the y-int is 0 and 0/3 is 0.
Hi im a bit stuck on this:
I can do the first part as its just a reflection on the bottom half. Im a bit confused on the second part. I know that f(ax) causes a squash factor a parallel to the x axis. So i know i need to squash it 3 times as much, but i dont know how to work out where the new intercept will be, and exactly what the new points are. Any suggestions?