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Thread: more factoring

  1. #1
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    more factoring

    more factoring...

    a) 21$\displaystyle x^5$$\displaystyle y^4$$\displaystyle z^6$-15$\displaystyle x^4$$\displaystyle y^2$$\displaystyle z^8$+36$\displaystyle x^8$$\displaystyle y^3$ z
    b)$\displaystyle x^3$-5x+4
    c)4$\displaystyle x^4$-8$\displaystyle x^3$-20$\displaystyle x^2$-48x
    d)$\displaystyle x^4$+$\displaystyle x^3$-4$\displaystyle x^2$+5x-3

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  2. #2
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    I've made some progress...not really, actually

    for a) i got 3$\displaystyle x^4$$\displaystyle y^2$z (7x$\displaystyle y^2$$\displaystyle z^5$-5$\displaystyle z^7$+12$\displaystyle x^4$y)......I'm not sure if this is the last step or if there's more...
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  3. #3
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    Hello, johett!

    The first one has a common factor . . . and that's all.

    The others require knowledge of the Factor Theorem.


    $\displaystyle a)\;21x^5y^4z^6 -15x^4y^2z^8+36x^8y^3z$
    $\displaystyle 3x^4y^2z\left(7xy^2z^5 - 5z^7 + 12x^4y\right)$ . . . You got it! . . .Good!


    $\displaystyle b) \;x^3 - 5x+4$
    $\displaystyle (x-1)(x^2+x-4)$


    $\displaystyle c)\;4x^4 -8x^3-20x^2-48x$
    $\displaystyle 4x(x-4)(x^2+2x+3)$


    $\displaystyle d) \;x^4+x^3-4x^2+5x-3$
    $\displaystyle (x-1)(x+3)(x^2-x+1)$

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