# Math Help - Pre-calculus Challenge!

1. ## Pre-calculus Challenge!

Who can help me do this challenge? I need urgent help please.

2. Originally Posted by rlarach
Who can help me do this challenge? I need urgent help please.
You have posted many of these numerous problems already (problems 3, 4 and 6 immediately come to mind, there's probably others) and help has been given for them. If that help was insufficient for you, I suggest you find the appropriate threads, show what working you've done and state where you're stuck.

Personally, I find this current post academically unethical, an insult to the intelligence of this forum and a gross abuse of this service. There may be some members who don't have a problem in doing all your assignment work for you, but from what I've seen here I doubt it. You've shown no evidence that you're willing to put any effort into your work or understanding the help you've been given - I think you'll find that such an attitude will result in very few future replies.

Bottom line: Show the work you've done, state where you're stuck. Show some effort.

3. ## agree

I also agree with "mr fantastic". I use this forum only when I have tried to do a problem and i get stuck. I enter in the problem, what work i have done and why. This also helps other help you. They can then fully understand you, and provide a fitting explanation.

4. Hello, rlarach!

Here's some help . . .

1) Determine the area of the region enclosed by the curve:
. . $|x-1| + |y-1| \:=\:1$
If we sketch the graph, the answer is obvious.
Code:
        |
|   (1,2)
|     *
|   *   *
| *       *
(0,1)*           *(2.1)
| *       *
|   *   *
- - + - - * - - - - -
|   (1,0)
|

2) Let x be a positive real number not equal to 1.
Determine the region of the x-y plane containing the solution
to the inequality: . $\log_x\left[\log_x(y^2)\right] \;>\;0$

We have: . $\log_x\left[\log_x\left(y^2\right)\right] \:>\:0\quad\Rightarrow\quad \log_x\left(y^2\right) \:>\:x^0$

Then: . $\log_x(y^2) \:>\:1\quad\Rightarrow\quad y^2 \:>\:x^1$

Hence: . $x\:<\:y^2$

Code:
      |::::: ::::::::*
|::::: :::*
|:::::*
|::*
|*
- + - - + - - -
|*    1
|::*
|:::::*
|::::: :::*
|::::: ::::::::*

This is the region to the left of the parabola: $x \,=\,y^2$
. . and to the right of the y-axis, except where $x = 1$