# Pre-calculus Challenge!

• Jan 5th 2008, 01:32 PM
rlarach
Pre-calculus Challenge!
Who can help me do this challenge? I need urgent help please.
• Jan 5th 2008, 01:55 PM
mr fantastic
Quote:

Originally Posted by rlarach
Who can help me do this challenge? I need urgent help please.

You have posted many of these numerous problems already (problems 3, 4 and 6 immediately come to mind, there's probably others) and help has been given for them. If that help was insufficient for you, I suggest you find the appropriate threads, show what working you've done and state where you're stuck.

Personally, I find this current post academically unethical, an insult to the intelligence of this forum and a gross abuse of this service. There may be some members who don't have a problem in doing all your assignment work for you, but from what I've seen here I doubt it. You've shown no evidence that you're willing to put any effort into your work or understanding the help you've been given - I think you'll find that such an attitude will result in very few future replies.

Bottom line: Show the work you've done, state where you're stuck. Show some effort.
• Jan 5th 2008, 05:42 PM
OnMyWayToBeAMathProffesor
agree
I also agree with "mr fantastic". I use this forum only when I have tried to do a problem and i get stuck. I enter in the problem, what work i have done and why. This also helps other help you. They can then fully understand you, and provide a fitting explanation.
• Jan 5th 2008, 07:19 PM
Soroban
Hello, rlarach!

Here's some help . . .

Quote:

1) Determine the area of the region enclosed by the curve:
. . $|x-1| + |y-1| \:=\:1$

If we sketch the graph, the answer is obvious.
Code:

        |         |  (1,2)         |    *         |  *  *         | *      *   (0,1)*          *(2.1)         | *      *         |  *  *     - - + - - * - - - - -         |  (1,0)         |

Quote:

2) Let x be a positive real number not equal to 1.
Determine the region of the x-y plane containing the solution
to the inequality: . $\log_x\left[\log_x(y^2)\right] \;>\;0$

We have: . $\log_x\left[\log_x\left(y^2\right)\right] \:>\:0\quad\Rightarrow\quad \log_x\left(y^2\right) \:>\:x^0$

Then: . $\log_x(y^2) \:>\:1\quad\Rightarrow\quad y^2 \:>\:x^1$

Hence: . $x\:<\:y^2$

Code:

      |::::: ::::::::*       |::::: :::*       |:::::*       |::*       |*     - + - - + - - -       |*    1       |::*       |:::::*       |::::: :::*       |::::: ::::::::*

This is the region to the left of the parabola: $x \,=\,y^2$
. . and to the right of the y-axis, except where $x = 1$