Solve the equation
log₃ (2 – 3x) = log₉ (6x^2 – 19x + 2)
How can I solve this? Please help.
The log bases haven't formatted properly. Assuming the same base on each side (if they're not, then you're gonna have to make it much clearer what the bases are) it follows that:
2 - 3x = 6x^2 - 19x + 2
=> 6x^2 - 16x = 0
=> .......
But be careful - check all potential solutions by subbing into the original equation. One of them must be discarded ......