Solve the equation

log₃ (2 – 3x) = log₉ (6x^2 – 19x + 2)

How can I solve this? Please help.

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- Jan 5th 2008, 01:58 AMgetonProblem in exponential and logarithms
Solve the equation

log₃ (2 – 3x) = log₉ (6x^2 – 19x + 2)

How can I solve this? Please help. - Jan 5th 2008, 02:21 AMmr fantastic
The log bases haven't formatted properly.

*Assuming*the same base on each side (if they're not, then you're gonna have to make it much clearer what the bases are) it follows that:

2 - 3x = 6x^2 - 19x + 2

=> 6x^2 - 16x = 0

=> .......

But be careful - check all potential solutions by subbing into the original equation. One of them must be discarded ...... - Jan 5th 2008, 02:50 AMwingless

Using this,

Then,

Now you can solve this equation for x.

(Don't forget that - Jan 5th 2008, 03:30 AMwgunther