Thread: is this complete ?

using the equation VT(power n) = C

cuttin speed tool life
180m/min 30
250m/min 12

v1=180
t1=30
v2=250
t2=12

logv1+logt1=log c
logv2+logt2=log c

log180+nlog30
log250+nlog12

2.255+n1.477
-2.397+n1.079
=-0.142+n-0.602=0

n=0.602 = 0.142

0.142
0.602
=0.235

180+0.235x1.477=180.3470

is this the end of the equation?

sorry missed out a bit of infomation n=0.13

Originally Posted by jenko

sorry missed out a bit of infomation n=0.13

But as I showed in my last post, n = 0.13 isn't going to work in your equation. If is correct for both sets of data then your problem is inconsistent.

Are you giving us the full problem? If so, then what are you trying to find?

-Dan

full equation:

a test was carried out on the centre lathe and the following results obtained:

Cutting speed (V) Tool life (T)
180m/min 30min
250m/min 12min

using the equation VT(small n at the top of T) = C

Originally Posted by jenko

full equation:

a test was carried out on the centre lathe and the following results obtained:

Cutting speed (V) Tool life (T)
180m/min 30min
250m/min 12min

using the equation VT(small n at the top of T) = C

So you are trying to find n and C?

-Dan

i think thats what its asking :S i am realy unsure i do not have any other infomation on this question

Originally Posted by jenko

full equation:

a test was carried out on the centre lathe and the following results obtained:

Cutting speed (V) Tool life (T)
180m/min 30min
250m/min 12min

using the equation VT(small n at the top of T) = C

Okay, start to finish, finding n and C. Here's how I would do this:
First


So















(which means I screwed up in my earlier post. )

Now we may take either set of data to find C:
180m/min 30min


-Dan