Results 1 to 2 of 2

Thread: Logarithmic Equation

  1. December 12th 2007, 05:16 PM #1
    Macleef
    Macleef is offline
    Member
    Joined
    Nov 2007
    Posts
    232

    Logarithmic Equation

    Did I do solve the following equation properly using the laws of logs + exponentials?

    Solve:
    log_5(log_4(log_3x)) = 1


    My Work:
    log_5(log_4(log_3x)) = 5^{log_5(log_4(log_3x))} = log_4(log_3x) = 5^{1} = 5

    (log_4(log_3x) = 4^{log_4(log_3x)} = 4^{5} = 1024

    log_3x = 3^{log_3x} = x = 3^{1024}


    Answer: 3^{1024}
    Follow Math Help Forum on Facebook and Google+
  2. December 12th 2007, 05:18 PM #2
    Krizalid
    Krizalid is offline
    Math Engineering Student
    Krizalid's Avatar
    Joined
    Mar 2007
    From
    Santiago, Chile
    Posts
    3,654
    Thanks
    5
    That's correct.
    Follow Math Help Forum on Facebook and Google+
« questions on xy plane | Logarithmic Equations »

Similar Math Help Forum Discussions

  1. Logarithmic equation
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: August 20th 2010, 11:07 PM
  2. Logarithmic Equation
    Posted in the Pre-Calculus Forum
    Replies: 5
    Last Post: May 10th 2010, 01:55 AM
  3. Logarithmic Equation
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: November 12th 2009, 11:54 AM
  4. logarithmic equation
    Posted in the Algebra Forum
    Replies: 2
    Last Post: April 26th 2008, 07:25 PM
  5. Logarithmic equation
    Posted in the Algebra Forum
    Replies: 6
    Last Post: March 18th 2008, 09:17 AM

Search Tags


/mathhelpforum @mathhelpforum