Hey, i was asked to find the co-ordinates of the points were the graph, y=x^2-7x+6 crosses the axis, to find this i did x =1,2,3-1,-2 etc and found the y value. i got that (0,6)(1,0)(6,0) crossed, but this looks a little strnage to draw a curve on the graph.... have i done it right?
Also what would be the best way of working out y=x(x-3)^2, so that i could sketch it?
I have a picture of a line AB tht eq is y=4x-5 and passes through the point 9(2,3). The line BC is perp to AB and cuts the x axis at C. I need tofind the equation of line BC, which i have done, but i also need to find the x coordinate of C, but im not sure how do it? thnx
Also how could i express 3(in a square root thing)
6-3(3 again in sqr root thing)
in the form of p+q 3(in sqroot)
Iv now with the help of you great people being able to complete my practise paper and practised and found some new tips lol thnx