1. ## Simple Evaluating Logarithmics

Is $logx$ defined for $x = 0$?

No, because x > 0. Is this correct?

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Evaluate:

1) $log( \frac {1}{10^2} )$

$-2$?

2) $log_3 \sqrt3$

$- \frac {1}{3}$ ?

3) $log_93$

$\sqrt3$ ?

Can you please check to see if I did the questions correctly?

2. Originally Posted by Macleef
Is $logx$ defined for $x = 0$?

No, because x > 0. Is this correct?
the domain of the logarithm is x > 0. because there is no power we can raise a number to to get 0

Evaluate:

1) $log( \frac {1}{10^2} )$

$-2$?
correct

2) $log_3 \sqrt3$

$- \frac {1}{3}$ ?
wrong. what is $\sqrt{3}$ written as 3 to some power?

3) $log_93$

$\sqrt3$ ?
wrong. what power do we have to raise 9 to to get 3?

3. Originally Posted by Jhevon
the domain of the logarithm is x > 0. because there is no power we can raise a number to to get 0

correct

wrong. what is $\sqrt{3}$ written as 3 to some power?

wrong. what power do we have to raise 9 to to get 3?
2) $\frac {1}{2}?$

3) $\frac {1}{2}?$

4. Originally Posted by Macleef
2) $\frac {1}{2}?$

3) $\frac {1}{2}?$