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Thread: Simple Evaluating Logarithmics

  1. #1
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    Simple Evaluating Logarithmics

    Is $\displaystyle logx$ defined for $\displaystyle x = 0$?

    No, because x > 0. Is this correct?


    ---

    Evaluate:

    1) $\displaystyle log( \frac {1}{10^2} )$

    My answer:
    $\displaystyle -2 $?

    2) $\displaystyle log_3 \sqrt3$

    My answer:
    $\displaystyle - \frac {1}{3}$ ?

    3) $\displaystyle log_93$

    My answer:

    $\displaystyle \sqrt3$ ?




    Can you please check to see if I did the questions correctly?

    Thanks in advance.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Macleef View Post
    Is $\displaystyle logx$ defined for $\displaystyle x = 0$?

    No, because x > 0. Is this correct?
    the domain of the logarithm is x > 0. because there is no power we can raise a number to to get 0

    Evaluate:

    1) $\displaystyle log( \frac {1}{10^2} )$

    My answer:
    $\displaystyle -2 $?
    correct

    2) $\displaystyle log_3 \sqrt3$

    My answer:
    $\displaystyle - \frac {1}{3}$ ?
    wrong. what is $\displaystyle \sqrt{3}$ written as 3 to some power?

    3) $\displaystyle log_93$

    My answer:

    $\displaystyle \sqrt3$ ?
    wrong. what power do we have to raise 9 to to get 3?
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  3. #3
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    Quote Originally Posted by Jhevon View Post
    the domain of the logarithm is x > 0. because there is no power we can raise a number to to get 0

    correct

    wrong. what is $\displaystyle \sqrt{3}$ written as 3 to some power?

    wrong. what power do we have to raise 9 to to get 3?
    2) $\displaystyle \frac {1}{2}?$

    3) $\displaystyle \frac {1}{2}?$
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Macleef View Post
    2) $\displaystyle \frac {1}{2}?$

    3) $\displaystyle \frac {1}{2}?$
    yes, those are the answers to your questions
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