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Math Help - Simple Evaluating Logarithmics

  1. #1
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    Simple Evaluating Logarithmics

    Is logx defined for x = 0?

    No, because x > 0. Is this correct?


    ---

    Evaluate:

    1)  log( \frac {1}{10^2} )

    My answer:
     -2 ?

    2) log_3 \sqrt3

    My answer:
     - \frac {1}{3} ?

    3) log_93

    My answer:

    \sqrt3 ?




    Can you please check to see if I did the questions correctly?

    Thanks in advance.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Macleef View Post
    Is logx defined for x = 0?

    No, because x > 0. Is this correct?
    the domain of the logarithm is x > 0. because there is no power we can raise a number to to get 0

    Evaluate:

    1)  log( \frac {1}{10^2} )

    My answer:
     -2 ?
    correct

    2) log_3 \sqrt3

    My answer:
     - \frac {1}{3} ?
    wrong. what is \sqrt{3} written as 3 to some power?

    3) log_93

    My answer:

    \sqrt3 ?
    wrong. what power do we have to raise 9 to to get 3?
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  3. #3
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    Quote Originally Posted by Jhevon View Post
    the domain of the logarithm is x > 0. because there is no power we can raise a number to to get 0

    correct

    wrong. what is \sqrt{3} written as 3 to some power?

    wrong. what power do we have to raise 9 to to get 3?
    2) \frac {1}{2}?

    3) \frac {1}{2}?
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Macleef View Post
    2) \frac {1}{2}?

    3) \frac {1}{2}?
    yes, those are the answers to your questions
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