# Simple Evaluating Logarithmics

• Dec 9th 2007, 05:13 PM
Macleef
Simple Evaluating Logarithmics
Is $logx$ defined for $x = 0$?

No, because x > 0. Is this correct?

---

Evaluate:

1) $log( \frac {1}{10^2} )$

$-2$?

2) $log_3 \sqrt3$

$- \frac {1}{3}$ ?

3) $log_93$

$\sqrt3$ ?

Can you please check to see if I did the questions correctly?

• Dec 9th 2007, 05:22 PM
Jhevon
Quote:

Originally Posted by Macleef
Is $logx$ defined for $x = 0$?

No, because x > 0. Is this correct?

the domain of the logarithm is x > 0. because there is no power we can raise a number to to get 0

Quote:

Evaluate:

1) $log( \frac {1}{10^2} )$

$-2$?
correct

Quote:

2) $log_3 \sqrt3$

$- \frac {1}{3}$ ?
wrong. what is $\sqrt{3}$ written as 3 to some power?

Quote:

3) $log_93$

$\sqrt3$ ?

wrong. what power do we have to raise 9 to to get 3?
• Dec 9th 2007, 05:28 PM
Macleef
Quote:

Originally Posted by Jhevon
the domain of the logarithm is x > 0. because there is no power we can raise a number to to get 0

correct

wrong. what is $\sqrt{3}$ written as 3 to some power?

wrong. what power do we have to raise 9 to to get 3?

2) $\frac {1}{2}?$

3) $\frac {1}{2}?$
• Dec 9th 2007, 05:37 PM
Jhevon
Quote:

Originally Posted by Macleef
2) $\frac {1}{2}?$

3) $\frac {1}{2}?$

yes, those are the answers to your questions