nb
Last edited by oceanmd; Dec 13th 2007 at 04:18 AM.
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$\displaystyle \frac{9!}{4!3!} = \frac{9\cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{4 \cdot 3 \cdot 2 \cdot 1 \cdot 3 \cdot 2 \cdot 1}$ Can you finish? What cancels out?
Originally Posted by oceanmd nb Not nice eh? I just see this. I dunno why you people delete your questions, it doesn't make any sense! It may be helpful for someone else!
Originally Posted by oceanmd nb Why did you delete this? Someone else might have benefited from this question!! -Dan
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