• Dec 9th 2007, 03:27 PM
oceanmd
nb
• Dec 9th 2007, 03:31 PM
ThePerfectHacker
$\frac{9!}{4!3!} = \frac{9\cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{4 \cdot 3 \cdot 2 \cdot 1 \cdot 3 \cdot 2 \cdot 1}$
Can you finish? What cancels out?
• Dec 14th 2007, 02:07 PM
Krizalid
Quote:

Originally Posted by oceanmd
nb

Not nice eh? I just see this.

I dunno why you people delete your questions, it doesn't make any sense! It may be helpful for someone else!
• Dec 14th 2007, 04:36 PM
topsquark
Quote:

Originally Posted by oceanmd
nb

Why did you delete this? Someone else might have benefited from this question!! :mad:

-Dan