nb
Last edited by oceanmd; Dec 13th 2007 at 04:58 AM.
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Originally Posted by oceanmd $\displaystyle 1/e+2/e^2+3/e^3+4/e^4+....+an$ (n lower than a) I am not sure how to do it. Is it sigma sign, on top n, on the botton k+1, next to it k/e^k Please write the correct solution. Thank you is this what you are describing? $\displaystyle \sum_{k = 1}^{n} \frac k{e^k}$
Originally Posted by oceanmd Yes, I am still learning how to code, but this is exactly what I meant. So is it correct? yes
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