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Math Help - Please find the 4th term in expansion

  1. #1
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    Please find the 4th term in expansion

    nb
    Last edited by oceanmd; December 13th 2007 at 06:04 AM.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by oceanmd View Post
    (x^2-y)^6

    {6\choose3}(x^2)^3(-y)^0=20x^6

    Wil you please check the solution and correct if it is wrong.

    Thank you
    why is the power of -y zero?
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by oceanmd View Post
    {6\choose3}(x^2)^3(-y)^3=20x^6(-y)^3

    Is it correct now?

    Thanks
    yes, using of course, (a + b)^n = \sum_{k = 0}^n {n \choose k}a^kb^{n - k}

    write it as -20x^6y^3
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