Thread: equations

Use the linear regression feature of a graphing calculator to calculate the equation of a line given the following two points that the line passes through: (12, 8) and (14, -6).

Using Linear Regression is overkill, but here's how I would do it on a TI-89.

Press APPS.

Select Stats/List Editor.

In List1[1], input 12
In List1[2], input 14
In List2[1], input 8
In List2[2], input -6

Now F4 (Calc) -> Regressions -> LinReg(ax+b)

Then input as follows (Press 2ND: VAR-LINK to search for the lists):
X List: List1
Y List: List2
Store RegEqn to: y1(x)

Then press ENTER one or two times.

You should get

Originally Posted by nikki

Use the linear regression feature of a graphing calculator to calculate the equation of a line given the following two points that the line passes through: (12, 8) and (14, -6).

Who would use linear regression to do this problem? I'm curious as to where it came from?

-Dan