If someone could tell me how to express the square root of something, I'll quickly put the problems up here. Thanks.

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- Dec 3rd 2007, 10:11 AMNash55Simplifying expressions
If someone could tell me how to express the square root of something, I'll quickly put the problems up here. Thanks.

- Dec 3rd 2007, 10:25 AMtopsquark
- Dec 3rd 2007, 10:40 AMNash55Thanks
If you could help simplifying these expressions, and showing the work, that'd be great. Thanks.

^3 sqrt(54x^4)

sqrt(32x^5)

sqrt(5x) multiplied by ^3 sqrt(5x)

5 sqrt (3) + 2 sqrt(12) - 2 sqrt(27)

( 4 sqrt (2) – sqrt (3) ) ( 5 sqrt (2) + 2 sqrt (3)) - Dec 3rd 2007, 10:58 AMtopsquark
- Dec 3rd 2007, 11:02 AMearboth
Hello,

I'm just guessing. I assume that you mean:

$\displaystyle \sqrt[3]{54x^4}=\sqrt[3]{27x^3 \cdot 2x}=3x \cdot \sqrt[3]{2x}$

$\displaystyle \sqrt{32x^5}=\sqrt{16x^4 \cdot 2x}= 4x^2 \cdot \sqrt{2x}$

With the next problem it's easiest if you use powers:

$\displaystyle \sqrt{5x} \cdot \sqrt[3]{5x}=(5x)^{\frac12} \cdot (5x)^{\frac13}=(5x)^{\frac12 + \frac13}=(5x)^{\frac56}$

I'll leave the rest for you. - Dec 3rd 2007, 12:26 PMNash55
Is this alright for

5 sqrt (3) + 2 sqrt (12) - 2 sqrt (27)=

3 sqrt (3) - Dec 3rd 2007, 02:42 PMtopsquark