
Helpppp!!!!
Heres the question exactly as is:
Tangents to the curve f(x)=4xx^2 intersect at (7/4,11/2). P and Q are points of tangency to the curve. Find the point of intersection of the normals drawn to the curve at points P and Q.
I can only find the point on the left of the curve but i cant find anything about the point ont he right. helppp mee (sorta urgent unit final tomorrow).
(p.s. the answers are (1/2,7/4) its not the anwser im after how to do it)

You can find the derivative of y to find the slope, m, at the points.
Try using $\displaystyle yy_{1}=m(xx_{1})$
$\displaystyle (4xx^{2})\frac{11}{2}=(42x)(x\frac{7}{4})$
Solve for x. That will be the xcoordinates of the points of intersection of the two tangent lines.
You can then find their equations and it's downhill.
