Umm...no, that's not what you get when you divide them.Originally Posted by mazdatuner
You want to take
Note that as x blows up, the most important terms are the x^2. So:
(Or you can just plug a large number, say x=10000, and see what you get.)
So we have a horizontal asymptote at y=2 on the +x side.
(Squaring takes away the "-" sign, so the expressions are the same.)
So we have the same horizontal asymptote on both sides of the y-axis: y=2.
It's a good idea to factor your expression here before we figure these. I'll show you why in a minute.
Generally you find vertical asymptotes where the denominator of the expression goes to zero. This means that x = 4 is a vertical asymptote. Normally x = -2 would be another, but the x+2 in the denominator is cancelled by the x+2 in the numerator. That's why you ALWAYS want to factor these things.
You get a slant asymptote only when the degree of the numerator is one more than the degree of the denominator. In this case they are both quadratics, so we don't have any slant asymptotes.
Not sure what you mean by this. Perhaps we are speaking of x = -2? This is a point in the domain that is not allowed.
This is where F(x) is zero. This will happen when the numerator goes to zero (assuming that none of these x values are where we have a zero in the denominator!) The only non-cancelling term in the numerator is the 2x-7, so if we set that to zero we find an x intercept at the point (7/2,0).
These are easy. Just set x = 0 in your function:
So we have a y intercept at (0, 7/4).