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  1. #1
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    Post line

    Write an equation of the line that is parallel to the given line that passes through the given point.


    y=-2x + 3 (y=4. x=4)?
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  2. #2
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    So y=mx+b. Since the new line must be parrallel to the first line, we know that the slope is the same (m=slope=-2). So y=-2x+b. Now we use the point we were given (4,4). So 4=-2(4)+b. Then we solve for b. So b=12.
    So the new line that is parrallel is y=-2x+12.
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  3. #3
    MHF Contributor kalagota's Avatar
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    another approach is to use the point-slope form.. in this case, there is no variable to solve.. just distribution and arithmetic..

    y - y_o = m(x - x_o), where m is the slope and (x_o,y_o) is the given point..

     y - 4 = -2(x - 4) \implies y = -2x + 8 + 4 = -2x + 12
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