An object is 2.55cm from a convex lens of 10.55cm focal length. where is the image located?

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- Mar 29th 2006, 03:58 AM #1TeckGuest

- Mar 29th 2006, 04:35 AM #2Originally Posted by
**Teck**

Here do=2.55 cm and f = 10.55 cm.

$\displaystyle \frac{1}{d_i}=\frac{1}{f}-\frac{1}{d_o}$

$\displaystyle \frac{1}{d_i}=\frac{1}{10.55}-\frac{1}{2.55} \approx -0.297370133$

$\displaystyle d_i \approx -3.36 $cm to 3 significant digits.

Note that di is negative (so the image is on the same side as the object), as it should be since do is inside the focal length.

-Dan