Thread: If sin θ < 0 and cos θ > 0, then the terminal point determined by θ is in:

1. If sin θ < 0 and cos θ > 0, then the terminal point determined by θ is in:

If sin θ < 0 and cos θ > 0, then the terminal point determined by θ is in:

For some reason I am thinking its D. quadrant 4? (because It's the quadrant where y < 0 and x > 0, which is quadrant 4.) is this right?

2. Re: If sin θ < 0 and cos θ > 0, then the terminal point determined by θ is in:

Originally Posted by realbrandon
If sin θ < 0 and cos θ > 0, then the terminal point determined by θ is in:

For some reason I am thinking its D. quadrant 4? (because It's the quadrant where y < 0 and x > 0, which is quadrant 4.) is this right?

No need to explain. You have it right.

-Dan

3. Re: If sin θ < 0 and cos θ > 0, then the terminal point determined by θ is in:

Hello, realbrandon!

Another approach . . .

$\displaystyle \text{If }\sin\theta < 0\text{ and }\cos\theta > 0,\,\text{ then the terminal point determined by }\theta\text{ is in: }$

. . $\displaystyle \text{A. Quad 2} \qquad \text{B. Quad 1} \qquad \text{C. Quad 3} \qquad \text{D. Quad 4}$

$\displaystyle \sin\theta$ is negative in Quad 3 and Quad 4.
$\displaystyle \cos\theta$ is positive in Quad 1 and Quad 4.

Therefore, $\displaystyle \theta$ is in Quad 4.

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If sin > 0 and cos > 0, then the terminal point determined by is in:

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