i was wondering if anyone knows how to complete a this type of question:
F(x)=-(x-2)2-5
( the italic 2 means squared)
A.) sketch the parabola
B.) domain and range
Hello,
from the given equation you know:
1. the graph is a parabola opening down
2. the vertex is at V(2,-5)
3. the axis of symmetry is x = 2
4. the parabola is normal (that means no transformations)
5. see attachment
to B:
there aren't any restrictions for x therefore the domain is $\displaystyle D_f=\mathbb{R}$
the y-value of the vertex is the maximum value of the function. Thus all other values are below (-5). Therefore the range is
$\displaystyle R_f=(-\infty, -5]$