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Math Help - equation question

  1. #1
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    equation question

    if i have the problem
    (x-1)2+(y-8)2=16
    can i just get make that into
    (x-1)+(y-8)=4?
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by brandilee View Post
    if i have the problem
    (x-1)2+(y-8)2=16
    can i just get make that into
    (x-1)+(y-8)=4?
    no, you cannot do that

    what do you want to do?
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  3. #3
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    If it is the equation of a circle then yes you may:

    Where (x-a)^2 + (y-b)^ 2 = r^2.......

    and r = the radius

    so take the sq root of 16, and you get 4, the radius.

    Hope this is clear....
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  4. #4
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    i have to graph it, and describe the shape and any other possible information like length, width and center points. im not sure how to put it into a calculator either
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  5. #5
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    Equation of a circle

    It's a circle with radius 4 (the Sq root of 16) and has points (1,8).
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by brandilee View Post
    i have to graph it, and describe the shape and any other possible information like length, width and center points. im not sure how to put it into a calculator either
    you don't have to change anything

    (x - 1)^2 + (y - 8)^2 = 16 = 4^2

    this is a circle with radius 4 centered at the point (1,8)
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  7. #7
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    so then for this problem
    (x+2)2+(y-4)2=36
    would be a circle with a radius of 6 and center poitn at (2,4)?
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  8. #8
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by brandilee View Post
    so then for this problem
    (x+2)2+(y-4)2=36
    would be a circle with a radius of 6 and center poitn at (2,4)?
    no, for the center, you change the signs. so the center here is (-2,4)


    The formula (x - h)^2 + (y - k)^2 = r^2 represents a circle with center (h,k) and radius r
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