log10 SQ of 10
I did
10^y=SQ of 10
Y=1/2 but I don't know how to that. I know I have to do something with the SQ of 10. It's not a perfect square. it comes out to 3.19.
Thanks
Jason
For any $\displaystyle a > 0$
$\displaystyle \sqrt[n]{a} = a^{1/n}$
We can prove this for the square roots fairly easily by solving $\displaystyle x^2 = a$ in two ways:
$\displaystyle x^2 = a$
$\displaystyle x = \sqrt{a}$ <-- Taking just the principle value for the moment.
And
$\displaystyle x^2 = a$
$\displaystyle (x^2)^{1/2} = a^{1/2}$
$\displaystyle x = a^{1/2}$
Thus
$\displaystyle \sqrt{a} = a^{1/2}$.
-Dan