Can you please check my answers.

Find the focus and directrix of the parabola with the given equation.

x^2=8y

I got:

focus: (0, 2)

directrix: y = -2

y^2=12x

I got:

focus: (3, 0)

directrix: x = -3

Match the equation to the graph.

y^2=8x

I got:

x^2=8y

I got:

Find the standard form of the equation of the parabola using the information given.Focus: (-15, 0); Directrix: x = 15

I got: y^2=-60x

Vertex: (8, -9); Focus: (8, -4)

I got: (x-8)^2=20(y+9)

Find the vertex, focus, and directrix of the parabola with the given equation.

(y-3)^2=4(x+2)

I got:

vertex: (2, -3)

focus: (3, -3)

directrix: x = 1

(x+2)^2=16(y-4)

I got:

vertex: (2, -4)

focus: (2, 0)

directrix: y = -8