Can you please check my answers?

Graph the ellipse and locate the foci.

9x^2=144-16y^2

I got

x^2/5+y^2/9=1

I got

Find the standard form of the equation of the ellipse and give the location of its foci.

I got: x^2/9 +y^2/4=1

foci at: (- squareroot of 5,0) and (squareroot 5,0)

I got: x^2/36+y^2/4=1

foci at: (0,-4 squareroot 2) and (0, 4 squareroot 2)