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Math Help - Logs

  1. #1
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    Joined
    Nov 2007
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    2

    Logs

    Hi all


    Anyone help with this problem?

    0.01 = 2.634 log (50.344/625S)

    What is the value of S?

    Any ideas how to calculate it? Any help appreciated.

    Thanks
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  2. #2
    Newbie
    Joined
    Oct 2007
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    14

    Calculators?

    Well, if you're allowed to use calculators, you can get S by using logarithmic identities:
    log(A/B) = logA - logB
    log(A*B) = logA + logB
    a = logb <=> 10^a = b (for log base 10)

    What I did:
    .01 = 2.634(log[50.344/(625*S)])
    .01 = 2.634[log(50.344) - log(625*S)]
    .01 = 2.634[log(50.344) - (log625 + logS)]
    .01/2.634 = log(50.344) - log625 - logS
    .01/2.634 - log(50.344) + log625 = - logS (multiply by -1)
    -.01/2.634 + log(50.344) - log625 = logS
    10^(-.01/2.634 + log(50.344) - log625) = S

    So, by my calculator: S = .0798493149
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  3. #3
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    Joined
    Nov 2007
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    Thanks a lot Epsilon
    That really clarifies how to go about solving the equation. And such a prompt response! Thanks again, very much appreciated
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