Hi all
Anyone help with this problem?
0.01 = 2.634 log (50.344/625S)
What is the value of S?
Any ideas how to calculate it? Any help appreciated.
Thanks
Well, if you're allowed to use calculators, you can get S by using logarithmic identities:
log(A/B) = logA - logB
log(A*B) = logA + logB
a = logb <=> 10^a = b (for log base 10)
What I did:
.01 = 2.634(log[50.344/(625*S)])
.01 = 2.634[log(50.344) - log(625*S)]
.01 = 2.634[log(50.344) - (log625 + logS)]
.01/2.634 = log(50.344) - log625 - logS
.01/2.634 - log(50.344) + log625 = - logS (multiply by -1)
-.01/2.634 + log(50.344) - log625 = logS
10^(-.01/2.634 + log(50.344) - log625) = S
So, by my calculator: S = .0798493149