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Math Help - graphing

  1. #1
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    graphing

    I'm trying to figure out the problem: X + 3Y > -1

    So far I have 3Y > -X-1

    This is where my problem is, I havent done these in so long..

    When I divide the 3 from the Y so that the Y is by itself, does the slope become -X/3, so that the answer is Y>-X/3 + 1/3, or does the slope become -1/3X, so that the answer is Y>-1/3X + 1/3?

    Thanks for the help this has been driving me nuts
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mitchelljk View Post
    I'm trying to figure out the problem: X + 3Y > -1

    So far I have 3Y > -X-1

    This is where my problem is, I havent done these in so long..

    When I divide the 3 from the Y so that the Y is by itself, does the slope become -X/3, so that the answer is Y>-X/3 + 1/3, or does the slope become -1/3X, so that the answer is Y>-1/3X + 1/3?

    Thanks for the help this has been driving me nuts
    the slope is the coefficient of X, which means it is just the number -1/3.

    it doesn't matter at all whether you write -X/3 or (-1/3)X, they are exactly the same thing
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  3. #3
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    Ok, and now that I have -1/3X, the rise of that slope is -1. and the run is 3, correct?
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mitchelljk View Post
    Ok, and now that I have -1/3X, the rise of that slope is -1. and the run is 3, correct?
    yeah. (well, technically it's not a rise, it's a fall, but whatever)
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