P = (4, -3, 7) Q = (-2, 5, 1) R= (3, 0, k) PR=QR What is K…… using normal algebra i got a slightly off answer.... arrggg
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Originally Posted by stones44 P = (4, -3, 7) Q = (-2, 5, 1) R= (3, 0, k) PR=QR What is K…… using normal algebra i got a slightly off answer.... arrggg we want $\displaystyle (4 - 3)^2 + (-3 - 0)^2 + (7 - k)^2 = (-2 - 3)^2 + (5 - 0)^2 + (1 - k)^2$ was that what you did? there should be much trouble working these out, the squares will cancel so you need only deal with a linear equation
yeah i got it...i was just off 1 number..that messed it ALL up
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