The voltage output (in volts) of an electrical circuit at time t seconds is given by the following function.
V(t) = 22 sin(5πt − 3π) + 1
(e) During the first second, determine when the voltage output of the circuit is 3 volts. (Enter your answers as a comma-separated list. Round your answers to four decimal places.)
My approach is to
1. set the function equal to 3
2. take the natural log to get rid of the exponent
t= (arcsin([ln3/ln2)-1]/2) + 3∏) / 5∏
I don't know if I'm on the right track so far, and I have no idea where to go from here? Any help would be soooooo great!! Thanks.