Write the expression log6x-1/5(log6x+2log6y) as a single logarithm.
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Do you mean express the following as a single logarithm?
$\displaystyle \log_6 x - \dfrac{1}{5\left(\log_6 x + 2\log_6 y\right)}$
Or did you mean this:
$\displaystyle \log (6 x) - \dfrac{1}{5\left(\log (6 x) + 2\log(6 y)\right)}$