Hey guys, just need help with lines today:
1. Calculate the distance between each of the following pair of points. (You may give your answer with the square root sign if necessary).
a) A (1,3) and B (5,6)
b) C (2,12) and D (14,7)
c) E (8,0) and F (0,6)
d) O (0,0) and H (9,-12)
e) I (8,2) and J (-2,-3)
f) K (-1,-3) and L (-8,1)
g) M (0,-5) and N (0,-1)
2. Find the perimeter of triangle ABC correct to 1 decimal place if the
coordinates of the vertices are
a) A (7,-9), B (0,0) and C (-2,-3)
b) A (-1,-1), B (-6,2) and C (3,-2)
3. If the vertices of triange PQR are P (-3,0), Q (1,-1) and R (0,3), show that triangle PQR is isosceles.
4. The points A (1,6), B (-4,3) and C (4,1) are the vertices of a triangle.
a) show that AB +AC =BC
b) Is triangle ABC a right-angled triangle?
5.
a) Given three points A (0,2), B (2,5) and C (4,8), calculate the lengths of AB, BC and AC.
b) Do the points A, B and C lie on the same straight line? Give reason.
A (1,3) and B (5,6)
Don't over think it, it's just the Pythagorean theorem. Each set of two points can be represented with a right triangle, where the length between the two points is the hypotenuse, the change in y is the height, and the change in x is the length. So i's just
If you have a hard time seeing this, try graphing the two points, then drawing a line straight down from the higher point, and then straight across (left or right) from the lower point to intersect the line created by the higher point, you will see it has created a right triangle. Then you can calculate the distance between the two by squaring the x distance and the y distance to get the hypotenuse squared. Then you just square root that to get the hypotenuse.