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Math Help - finding z1 , z2 of complex numer

  1. #1
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    finding z1 , z2 of complex numer

    finding z1 , z2 of complex numer-popp.jpgin order to get z1 and z2 , i tried to express z^2 into polar form, but z is to the power of 2, i'm not sure whether it can be epressed in polar form of not. by the way , here's my working. how should i proceed? i dont think my ans is correct.
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    Re: finding z1 , z2 of complex numer

    Quote Originally Posted by delso View Post
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ID:	31051in order to get z1 and z2 , i tried to express z^2 into polar form, but z is to the power of 2, i'm not sure whether it can be epressed in polar form of not. by the way , here's my working. how should i proceed? i dont think my ans is correct.
    Please learn some basic LaTeX. It is hard enough to read from an image,
    On top of that, why should we read your scratching?
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    Re: finding z1 , z2 of complex numer

    $\text{Arg}(1-2\sqrt 2 i)=\arctan(-2 \sqrt 2)=\theta$

    ${z_1} = \sqrt 3 \exp \left( {\frac{\theta }{2} } \right)\;\& \;{z_2} = \sqrt 3 \exp \left( {\frac{\theta+\pi }{2 }} \right)$
    Last edited by Plato; May 31st 2014 at 01:38 PM.
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    Re: finding z1 , z2 of complex numer

    Quote Originally Posted by Plato View Post
    $\text{Arg}(1-2\sqrt 2 i)=\arctan(-2 \sqrt 2)=\theta$

    ${z_1} = \sqrt 3 \exp \left( {\frac{\theta }{2} } \right)\;\& \;{z_2} = \sqrt 3 \exp \left( {\frac{\theta+\pi }{2 }} \right)$
    can you please show me how do u express z^2 in polar form step by step, i have done it in the very first post, but i dont think it's correct. my ans is weird. i cant understand your working in post 3
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