1. ## some integers

The solution to (2^x)(e^(3x+1))=10 is (p + ln q)/(r+ln s), where all of p, q, r and s are integers. D=p+q+r+s.

2. ## Re: some integers

The solution to $(2^x)(e^{3x+1})=10$ is (p + ln q)/(r+ln s), where all of p, q, r and s are integers. D=p+q+r+s.
The solution of $(2^x)(e^{3x+1})=10$ for $x$ is
$x\log(2)+(3x+1)=\log(10)\\x=\dfrac{\log(10)-1}{\log(2)+3}$

3. ## Re: some integers

The solution to (2^x)(e^(3x+1))=10 is (p + ln q)/(r+ln s), where all of p, q, r and s are integers. D=p+q+r+s.
What is D in this context? I'm at a loss.

-Dan

4. ## Re: some integers

D is just the sum of the 4 integers p,q,r,s
So here what I need to know is

p=?
q=?
r=?
s=?