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Math Help - vector equation of a plane

  1. #1
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    vector equation of a plane

    vector equation of a plane-dsc_0001-7-1-.jpgvector equation of a plane-dsc_0001-8-1-.jpgvector equation of a plane-dsc00130-2-1-.jpg
    for this question (photo 1), i am not sure whether this is type 1 (as the type in photo 2) or type 2 ( as in photo 3 ). the question didnt provide a diagram, this is making me confused. so i did it another way on the right , (using pencil ). is my working acceptable ?
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  2. #2
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    Re: vector equation of a plane

    Quote Originally Posted by delso View Post
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    for this question (photo 1), i am not sure whether this is type 1 (as the type in photo 2) or type 2 ( as in photo 3 ). the question didnt provide a diagram, this is making me confused. so i did it another way on the right , (using pencil ). is my working acceptable ?
    I have absolutely no idea what your post means.
    In general if $A,~B,~\&~C$ are three non-colinear then the plane determined is:
    Let $R=<x,y,z>$ then the plane is $\left( {\overrightarrow {AB} \times \overrightarrow {AC} } \right) \cdot \left[ {\overrightarrow R - \overrightarrow A } \right] = 0$
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  3. #3
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    Re: vector equation of a plane

    how do u know a b and c are not collinear?
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    Re: vector equation of a plane

    my question is how would we know whether A is connected to C or B is connected to C ? If A is connected to C , then the solution is just like case 1 (photo 2 ), and vice versa
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    Re: vector equation of a plane

    Quote Originally Posted by delso View Post
    my question is how would we know whether A is connected to C or B is connected to C ? If A is connected to C , then the solution is just like case 1 (photo 2 ), and vice versa
    They are not col-linear if $\overrightarrow {AB} \times \overrightarrow {AC} \ne 0$
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  6. #6
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    Re: vector equation of a plane

    in order to satisfy the condition r dot n = a dot n . the n which is the normal to the plane must originate from point a am i right? so the point a must be connected DIRECTLY to point B and point P , SO the angle between BAP can be found, but for photo 3, the point A is connected to B , but point P is connected to point B , but not A !. please correct me if my concept is wrong. VECTOR almost making me crazy.
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