Please write as single logarithm 4 log 7 (base) x + 3 log 7 (base) (x-2) Is this answer correct? log 7 (base) x^4 (x-2)^3 Thank you
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$\displaystyle 4\log_7x+3\log_7(x-2)=\log_7x^4+\log_7(x-2)^3=\log_7[x^4(x-2)^3]$
Thank you
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