Please write as single logarithm

4 log 7 (base) x + 3 log 7 (base) (x-2)

Is this answer correct? log 7 (base) x^4 (x-2)^3

Thank you

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- Nov 15th 2007, 08:34 AMoceanmdWrite as single logarithm
Please write as single logarithm

4 log 7 (base) x + 3 log 7 (base) (x-2)

Is this answer correct? log 7 (base) x^4 (x-2)^3

Thank you - Nov 15th 2007, 11:25 AMred_dog
$\displaystyle 4\log_7x+3\log_7(x-2)=\log_7x^4+\log_7(x-2)^3=\log_7[x^4(x-2)^3]$

- Nov 15th 2007, 11:47 AMoceanmd
Thank you