Find an equation of variation in which y varies inversely as x and the following condition exists: 1) y=63 when x=1/7
is the answer:
A) y = 9/x
B) y= 2/x
C) y= 16/x
D) y = 7/x
$\displaystyle y$ varies inversely as $\displaystyle x$ beans that there is a constantOriginally Posted by kharris82
$\displaystyle k$ such that:
$\displaystyle
y=\frac{k}{x}
$.
Now when $\displaystyle x=1/7$, $\displaystyle y=63$, so:
$\displaystyle
63=\frac{k}{1/7}=7k
$,
hence $\displaystyle k=63/7=9$, and so:
$\displaystyle
y=\frac{9}{x}
$,
which is answer A)
RonL